The atom $\begin{array} { c }
223 \
87
\end{array}$ Fr decays to $\begin{array} { c }
223 \
88
\end{array}$ Ra by emitting what kind of nuclear radiation?

Question

The atom $\begin{array} { c } 
223 \
87
\end{array}$ Fr decays to $\begin{array} { c } 
223 \
88
\end{array}$ Ra by emitting what kind of nuclear radiation?

Quizplus · Accepted Answer

The decay from Francium-223 to Radium-223 involves an increase in the atomic number from 87 to 88, which indicates the emission of a beta-minus particle (an electron), as a neutron is converted into a proton.

The Atom 22387\begin{array} { c } 223 \\87\end{array}22387​ Fr Decays To 22388\begin{array} { c } 223 \\88\end{array}22388​

The Atom $\begin{array} { c } 223 \\87\end{array}$ Fr Decays To $\begin{array} { c } 223 \\88\end{array}$