The neutral deuterium atom, $\begin{array} { l } 2 \ 1 \end{array}$ H, has a mass of 2.014102 u; a neutral ordinary hydrogen atom has a mass of 1.007825 u; a neutron has a mass of 1.008665 u; and a proton has a mass of 1.007277 u. What is the binding energy of the deuterium nucleus? (1 u = 931.5 MeV/c²)

Question

Quizplus · Accepted Answer

The binding energy is calculated by finding the mass defect: (mass of proton + mass of neutron - mass of deuterium). The mass defect is 0.002388 u, which converts to energy using 1 u = 931.5 MeV/c², resulting in approximately 2.2 MeV.

The Neutral Deuterium Atom 21\begin{array} { l } 2 \\1\end{array}21​ H, Has a Mass of 2

The Neutral Deuterium Atom $\begin{array} { l } 2 \\1\end{array}$ H, Has a Mass of 2