The half-life of radon-222 is 3.83 d.If a sample of radon initially contains 6.00 × 10⁸ radon atoms,how many of them are left after 10.0 d?

Question

Quizplus · Accepted Answer

Using the formula for radioactive decay: 
N = N0*(1/2)^(t/T), 
where N is the final number of atoms, N0 is the initial number of atoms, t is the time elapsed, and T is the half-life.

Plugging in the given values: 
N = (6.00 × 10^18)*(1/2)^(10/3.83), 
N = 9.82 × 10^17

Therefore, the correct answer is A, which is closest to 9.82 × 10^17.

The Half-Life of Radon-222 Is 3