What is the greatest magnitude of the orbital angular momentum L that you can find in a state with $n = 6 ?$

Question

Quizplus · Accepted Answer

The greatest magnitude of the orbital angular momentum L for a given principal quantum number n is given by $ L = \sqrt{l(l+1)} \frac{h}{2\pi} $, where $ l $ is the azimuthal quantum number and can take values from 0 to $ n-1 $. For $ n = 6 $, the maximum $ l $ is 5. Thus, $ L = \sqrt{5(5+1)} \frac{h}{2\pi} = \sqrt{30} \frac{h}{2\pi} \approx 5.48 \frac{h}{2\pi} $.

What Is the Greatest Magnitude of the Orbital Angular Momentum n=6?n = 6 ?n=6?

What Is the Greatest Magnitude of the Orbital Angular Momentum $n = 6 ?$