A helium-neon laser emits light at 632.8 nm. If the laser emits $1.82 \times 10 ^ { 17 }$ photons/second, what is its power output in mW? (c = 3.00 × 10⁸ m/s, h = 6.626 × 10^-34 J ? s) A)57.2 mW B)28.6 mW C)37.2 mW D)45.7 mW

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Quizplus · Accepted Answer

The energy of a single photon is given by E = hc/λ, where h is Planck's constant, c is the speed of light, and λ is the wavelength of the light. The power output of the laser is the total energy emitted per second, which is equal to the number of photons emitted per second multiplied by the energy of each photon. Therefore, the power output is:P = (1.82 × 10^17 photons/second) × (6.626 × 10^-34 J ? s) × (3.00 × 10^8 m/s) / (632.8 × 10^-9 m) = 57.2 mW

A Helium-Neon Laser Emits Light at 632 1.82×10171.82 \times 10 ^ { 17 }1.82×1017

A Helium-Neon Laser Emits Light at 632 $1.82 \times 10 ^ { 17 }$