A flat circular loop of radius 0.10 m is rotating in a uniform magnetic field of 0.20 T.Find the magnetic flux through the loop when the plane of the loop and the magnetic field vector are perpendicular. A)0 T ∙ m² B)3.1 × 10^-3 T ∙ m² C)5.5 × 10^-3 T ∙ m² D)6.3 × 10^-3 T ∙ m²

Question

Quizplus · Accepted Answer

The magnetic flux through a loop is given by the formula Φ = B*A*cos(θ), where Φ is the magnetic flux, B is the magnetic field strength, A is the area of the loop, and θ is the angle between the magnetic field and the normal to the plane of the loop. When the plane of the loop and the magnetic field vector are perpendicular, θ = 0 degrees, and cos(0) = 1. The area of a circle is A = πr^2, where r is the radius. Substituting the given values, A = π*(0.10 m)^2 = π*0.01 m^2. Therefore, Φ = 0.20 T * π * 0.01 m^2 = 0.20 * π * 0.01 T*m^2 ≈ 6.3 × 10^-3 T*m^2.

A Flat Circular Loop of Radius 0