A radio transmitter is operating at an average power of $4.00 \mathrm {~kW}$ and is radiating uniformly in all directions. What is the average intensity of the signal $8.00 \mathrm {~km}$ from the transmitter? A)4.97 ?W/m² B)2.49 ?W/m² C)0.00497 W/m² D)0.00249 W/m²

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Quizplus · Accepted Answer

The average intensity of the signal is given by:$$I = \frac{P}{4\pi r^2}$$where:* $P$ is the average power of the transmitter* $r$ is the distance from the transmitterSubstituting the given values into the equation, we get:$$I = \frac{4.00 \mathrm{~kW}}{4\pi (8.00 \mathrm{~km})^2} = 4.97 \times 10^{-6} \mathrm{~W/m^2}$$Therefore, the average intensity of the signal $8.00 \mathrm{~km}$ from the transmitter is $4.97 \times 10^{-6} \mathrm{~W/m^2}$.

A Radio Transmitter Is Operating at an Average Power Of 4.00