The rate of energy flow per unit area of a sinusoidal electromagnetic wave has an average value of 0.601 W/m².What is the maximum value of the magnetic field in the wave? (c = 3.00 × 10⁸ m/s,μ₀ = 4π × 10^-7 T ∙ m/A,ε₀ = 8.85 × 10^-12 C²/N ∙ m²) A)7.09 × 10^-8_T B)5.02 × 10^-8_T C)3.55 × 10^-8_T D)9.81 × 10^-8_T E)1.42 × 10^-7_T

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The average power per unit area is given by:$$S_{avg}=\frac{1}{2}\epsilon_0cE_0^2$$where:* S_avg is the average power per unit area* ε₀ is the permittivity of free space* c is the speed of light* E₀ is the maximum electric field strengthThe maximum magnetic field strength is related to the maximum electric field strength by:$$B_0=\frac{E_0}{c}$$Substituting the given values into the first equation, we get:$$0.601 ext{ W/m}^2=\frac{1}{2}(8.85 imes10^{-12} ext{ C}^2/ ext{N}\cdot ext{m}^2)(3.00 imes10^8 ext{ m/s})E_0^2$$Solving for E₀, we get:$$E_0=1.00 imes10^4 ext{ V/m}$$Substituting this value into the second equation, we get:$$B_0=\frac{1.00 imes10^4 ext{ V/m}}{3.00 imes10^8 ext{ m/s}}=3.33 imes10^{-5} ext{ T}$$Therefore, the maximum value of the magnetic field in the wave is 3.33 × 10^-5 T.

The Rate of Energy Flow Per Unit Area of a Sinusoidal