Light of intensity S₀ that is polarized horizontally passes through three ideal polarizers. The first and third are horizontal, but the second one is oriented at $0.39270 \mathrm { rad }$ to the horizontal. In terms of S₀, the intensity of the light that passes through the set of polarizers is closest to which one of the following choices? A)0.729 S₀ B)0.125 S₀ C)0.427 S₀ D)0.854 S₀

Question

Quizplus · Accepted Answer

The light intensity after passing through the first polarizer is S₀. After passing through the second polarizer, the intensity becomes S₀cos²(0.39270 rad) = 0.729 S₀. The third polarizer does not change the intensity, so the final intensity is 0.729 S₀.

Light of Intensity S0 That Is Polarized Horizontally Passes Through 0.39270rad0.39270 \mathrm { rad }0.39270rad

Light of Intensity S₀ That Is Polarized Horizontally Passes Through $0.39270 \mathrm { rad }$