Consider an ideal solenoid of length L,N windings,and radius b (L is much longer than b).A current I is flowing through the wire windings.If the length of the solenoid becomes twice as long (to 2L),but all other quantities remained the same,the magnetic field inside the solenoid will
A)remain the same.
B)become twice as strong as initially.
C)become one-half as strong as initially.
D)become four times as strong as initially.
E)become one-fourth as strong as initially.

Question

Quizplus · Accepted Answer

The magnetic field inside an ideal solenoid is given by B = μ₀(N/L)I. If the length L is doubled to 2L while N and I remain the same, the magnetic field becomes B = μ₀(N/2L)I, which is half of the initial magnetic field.

Consider an Ideal Solenoid of Length L,N Windings,and Radius B