An electron moving perpendicular to a uniform magnetic field of 0.22 T moves in a circle with a speed of 1.5 × 10⁷ m/s.What is the radius of the circle? (e = 1.60 × 10^-19 C,m_electron = 9.11 × 10^-31kg) A)1.5 mm B)0.22 mm C)2.2 mm D)0.39 mm E)3.9 mm

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Quizplus · Accepted Answer

The radius of the circle is given by the formula r = mv/(eB). Substituting the given values: r = (9.11 × 10^-31 kg * 1.5 × 10^7 m/s) / (1.60 × 10^-19 C * 0.22 T) = 3.9 mm.

An Electron Moving Perpendicular to a Uniform Magnetic Field of 0.22