An electron is accelerated from rest through a potential difference of 3.75 kV.It enters a region where a uniform 4.0-mT magnetic field is perpendicular to the velocity of the electron.Calculate the radius of the path this electron will follow in the magnetic field.(e = 1.60 × 10^-19 C,m_electron = 9.11 × 10^-31 kg) A)1.2 cm B)2.2 cm C)3.2 cm D)4.2 cm E)5.2 cm

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The Answer of An electron is accelerated from rest through a potential difference of 3.75 kV.It enters a region where a uniform 4.0-mT magnetic field is perpendicular to the velocity of the electron.Calculate the radius of the path this electron will follow in the magnetic field.(e = 1.60 × 10^-19 C,m_electron = 9.11 × 10^-31 kg) A)1.2 cm B)2.2 cm C)3.2 cm D)4.2 cm E)5.2 cm

An Electron Is Accelerated from Rest Through a Potential Difference