A straight wire carries a current of 10 A at an angle of 30° with respect to the direction of a uniform 0.30-T magnetic field.Find the magnitude of the magnetic force on a 0.50-m length of the wire.
A)0.75 N
B)1.5 N
C)3.0 N
D)6.0 N

Question

Quizplus · Accepted Answer

The magnitude of the magnetic force on a current-carrying wire in a magnetic field is given by $F = BIL\sin(\theta)$, where $B$ is the magnetic field strength, $I$ is the current, $L$ is the length of the wire, and $\theta$ is the angle between the wire and the magnetic field. Substituting the given values: $F = 0.30 \, \text{T} \times 10 \, \text{A} \times 0.50 \, \text{m} \times \sin(30^\circ) = 0.75 \, \text{N}$.

A Straight Wire Carries a Current of 10 a at an Angle