A flat circular coil has 200 identical loops of very thin wire.Each loop has an area of 0.12 m² and carries 0.50 A of current.This coil is placed in a magnetic field of 0.050 T oriented at 30° to the plane of the loop.What is the magnitude of the magnetic torque on the coil? A)0.25 N ∙ m B)0.52 N ∙ m C)2.5 N ∙ m D)5.2 N ∙ m

Question

Quizplus · Accepted Answer

The magnetic torque on a current-carrying loop in a magnetic field is given by:

τ = NIABsinθ

where N is the number of turns in the loop, I is the current, A is the area of each turn, B is the magnetic field, and θ is the angle between the plane of the loop and the direction of the magnetic field.

Substituting the given values, we get:

τ = (200)(0.50 A)(0.12 m2)(0.050 T)sin30°
   = 0.52 N ∙ m

Therefore, the magnitude of the magnetic torque on the coil is 0.52 N ∙ m, which corresponds to choice (B).

A Flat Circular Coil Has 200 Identical Loops of Very