A wire carrying a current is shaped in the form of a circular loop of radius 4.0 mm. If the magnetic field strength at its center is $1.1 \mathrm { mT }$ with no external magnetic fields present, what is the magnitude of the current flowing through the wire? (?₀ = 4? × 10^-7 T ? m/A) A)7.0 A B)28 A C)14 A D)17 A

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The magnetic field at the center of a circular loop of wire is given by:$$B = \frac{\mu_0 I}{2R}$$where:* B is the magnetic field strength* $\mu_0$ is the permeability of free space* I is the current flowing through the wire* R is the radius of the loopWe are given that:* B = 1.1 mT = 1.1 x 10^-3 T* $\mu_0$ = 4π x 10^-7 T m/A* R = 4.0 mm = 4.0 x 10^-3 mSolving for I, we get:$$I = \frac{2BR}{\mu_0} = \frac{2(1.1 	imes 10^{-3} 	ext{ T})(4.0 	imes 10^{-3} 	ext{ m})}{4\pi 	imes 10^{-7} 	ext{ T m/A}} = 7.0 	ext{ A}$$Therefore, the magnitude of the current flowing through the wire is 7.0 A.

A Wire Carrying a Current Is Shaped in the Form 1.1mT1.1 \mathrm { mT }1.1mT

A Wire Carrying a Current Is Shaped in the Form $1.1 \mathrm { mT }$