A 5.0-μF,a 14-μF,and a 21-μF capacitor are connected in series.How much capacitance would a single capacitor need to have to replace the three capacitors?
A)40 μF
B)3.6 μF
C)2.0 μF
D)3.1 μF

Question

Quizplus · Accepted Answer

When capacitors are connected in series, the total capacitance (C_total) is given by the reciprocal of the sum of the reciprocals of the individual capacitances: 1/C_total = 1/C1 + 1/C2 + 1/C3. For the given capacitors, 1/C_total = 1/5 + 1/14 + 1/21. Solving this gives C_total ≈ 3.1 μF.

A 50-μF,a 14-μF,and a 21-μF Capacitor Are Connected in Series