A 22-A current flows into a parallel combination of 4.0-Ω,6.0-Ω,and 12-Ω resistors.What current flows through the 12-Ω resistor?
A)18 A
B)11 A
C)7.3 A
D)3.7 A

Question

Quizplus · Accepted Answer

The total resistance (R_total) of the parallel combination can be calculated using the formula 1/R_total = 1/R1 + 1/R2 + 1/R3. Substituting the given values, we get 1/R_total = 1/4 + 1/6 + 1/12 = 1/2, so R_total = 2 Ω. The total current (I_total) is given as 22 A, and the total voltage across the combination can be found using Ohm's law (V = I_total * R_total), which gives V = 22 A * 2 Ω = 44 V. The current through the 12-Ω resistor (I_12) can then be found using Ohm's law again (I_12 = V / 12 Ω), resulting in I_12 = 44 V / 12 Ω = 3.7 A.

A 22-A Current Flows into a Parallel Combination of 4