A tube of mercury with resistivity 9.84 × 10^-7 Ω ∙ m has a uniform electric field of 23 N/C inside the mercury.How much current is flowing in the tube,if the radius of the tube is 0.495 mm? A)18 A B)180 A C)29 A D)280 A

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The current flowing in the tube can be calculated using the formula:I = (E * π * r^2) / ρwhere:I is the current in amperes (A)E is the electric field strength in volts per meter (V/m)r is the radius of the tube in meters (m)ρ is the resistivity of the material in ohm-meters (Ω∙m)Plugging in the given values, we get:I = (23 V/m * π * (0.495 mm)^2) / (9.84 × 10^-7 Ω∙m)I ≈ 18 ATherefore, the correct answer is A) 18 A.

A Tube of Mercury with Resistivity 9