A capacitor has a voltage of $391 \mathrm {~V}$ applied across its plates, and then the voltage source is removed. What is the potential difference across its plates if the space between them is then filled with mica, having a dielectric constant of 5.4?

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Quizplus · Accepted Answer

When a dielectric is inserted into a capacitor, the potential difference across its plates decreases by a factor equal to the dielectric constant. Therefore, the new potential difference is $391 \mathrm {~V} / 5.4 = 72 \mathrm {~V}$.

A Capacitor Has a Voltage Of 391 V391 \mathrm {~V}391 V Applied Across Its Plates, and Then the Voltage Source Is

A Capacitor Has a Voltage Of $391 \mathrm {~V}$ Applied Across Its Plates, and Then the Voltage Source Is