A hydrogen nucleus,which has a charge +e,is situated to the left of a carbon nucleus,which has a charge +6e.Which statement is true?
A)The electrical force experienced by the hydrogen nucleus is to the left,and the magnitude is equal to the force exerted on the carbon nucleus.
B)The electrical force experienced by the hydrogen nucleus is to the left,and the magnitude is greater than the force exerted on the carbon nucleus.
C)The electrical force experienced by the hydrogen nucleus is to the left,and the magnitude is less than the force exerted on the carbon nucleus.
D)The electrical force experienced by the hydrogen nucleus is to the right,and the magnitude is equal to the force exerted on the carbon nucleus.

Question

Quizplus · Accepted Answer

The electrical force between two charges is given by Coulomb's law:$$F = k\frac{q_1q_2}{r^2}$$where k is Coulomb's constant, q1 and q2 are the charges of the two particles, and r is the distance between them.In this case, the hydrogen nucleus has a charge of +e and the carbon nucleus has a charge of +6e. The distance between them is not given, but it is not relevant to the question.The electrical force between the two nuclei is:$$F = k\frac{(+e)(+6e)}{r^2} = +6ke^2/r^2$$The force is positive, which means that it is repulsive. The hydrogen nucleus will experience a force to the left, away from the carbon nucleus. The magnitude of the force is equal to the force exerted on the carbon nucleus, since the charges are equal in magnitude but opposite in sign.

A Hydrogen Nucleus,which Has a Charge +E,is Situated to the Left