What is the magnitude of a the vertical electric field that will balance the weight of a plastic sphere of mass $2.1 \mathrm {~g}$ that has been charged to -3.0 nC? (k = 1/4??₀ = 9.0 × 10⁹ N ? m²/C²) A)6.9 × 10⁶ N/C B)7.8 × 10⁵ N/C C)1.5 × 10⁶ N/C D)2.1 × 10⁶ N/C

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Quizplus · Accepted Answer

The electric force on the sphere is qE, where q is the charge on the sphere and E is the electric field. The weight of the sphere is mg, where m is the mass of the sphere and g is the acceleration due to gravity. If the electric force balances the weight of the sphere, then qE = mg. Solving for E, we get E = mg/q. Plugging in the given values, we get E = (2.1 × 10^-3 kg)(9.8 m/s^2)/(3.0 × 10^-9 C) = 6.9 × 10^6 N/C.

What Is the Magnitude of a the Vertical Electric Field 2.1 g2.1 \mathrm {~g}2.1 g

What Is the Magnitude of a the Vertical Electric Field $2.1 \mathrm {~g}$