One of the dangers of tornados and hurricanes is the rapid drop in air pressure that is associated with such storms. Assume that the air pressure inside of a sealed house is 1.02 atm when a hurricane hits. The hurricane rapidly decreases the external air pressure to 0.910 atm. What net outward force is exerted on a square window of the house that is $2.03 \mathrm {~m}$ on each side? (1.00 atm = 1.01 × 10⁵ Pa)

Question

Quizplus · Accepted Answer

The net outward force is equal to the difference in pressure between the inside and outside of the house multiplied by the area of the window.$$F = (P_{in} - P_{out})A$$$$F = (1.02 \mathrm{~atm} - 0.910 \mathrm{~atm})(2.03 \mathrm{~m})^2(1.01 	imes 10^5 \mathrm{~Pa/atm})$$$$F = 4.59 	imes 10^4 \mathrm{~N}$$

One of the Dangers of Tornados and Hurricanes Is the Rapid