How much heat is required to raise the temperature of a 225-g lead ball from 15.0°C to 25.0°C? The specific heat of lead is 128 J/kg ∙ K.
A)725 J
B)576 J
C)145 J
D)217 J
E)288 J

Question

Quizplus · Accepted Answer

The amount of heat required can be calculated using the formula $q = mc\Delta T$, where $q$ is the heat absorbed or released, $m$ is the mass of the substance, $c$ is the specific heat capacity, and $\Delta T$ is the change in temperature. Here, $m = 225 \, \text{g} = 0.225 \, \text{kg}$, $c = 128 \, \text{J/kg} \cdot \text{K}$, and $\Delta T = 25.0°C - 15.0°C = 10.0°C$. Thus, $q = 0.225 \, \text{kg} \times 128 \, \text{J/kg} \cdot \text{K} \times 10.0 \, \text{K} = 288 \, \text{J}$.

How Much Heat Is Required to Raise the Temperature of a 225-G