How much heat must be removed from 456 g of water at 25.0°C to change it into ice at -10.0°C? The specific heat of ice is 2090 J/kg ∙ K,the latent heat of fusion of water is 33.5 × 10⁴ J/kg,and the specific heat of water is 4186 J/kg ∙ K. A)105 kJ B)153 kJ C)57.3 kJ D)47.7 kJ E)210 kJ

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The Answer of How much heat must be removed from 456 g of water at 25.0°C to change it into ice at -10.0°C? The specific heat of ice is 2090 J/kg ∙ K,the latent heat of fusion of water is 33.5 × 10⁴ J/kg,and the specific heat of water is 4186 J/kg ∙ K. A)105 kJ B)153 kJ C)57.3 kJ D)47.7 kJ E)210 kJ

How Much Heat Must Be Removed from 456 G of Water