Heat is added to a 3.0 kg piece of ice at a rate of $636.0 \mathrm {~kW}$ How long will it take for the ice at 0.0° C to melt? For water L_F = 334,000 J/kg and L_V = 2.246 × 10⁶ J/kg.

Question

Quizplus · Accepted Answer

The energy required to melt the ice is calculated using the formula $Q = m \times L_F$. For 3.0 kg of ice, $Q = 3.0 \times 334,000 = 1,002,000 \, \text{J}$. The time taken is $t = \frac{Q}{P} = \frac{1,002,000}{636,000} \approx 1.6 \, \text{s}$.

Heat Is Added to a 3 636.0 kW636.0 \mathrm {~kW}636.0 kW How Long Will It Take for the Ice at 0

Heat Is Added to a 3 $636.0 \mathrm {~kW}$ How Long Will It Take for the Ice at 0