An ideal Carnot engine extracts 529 J of heat from a high-temperature reservoir during each cycle, and rejects $225 \mathrm {~J}$ of heat to a low-temperature reservoir during the same cycle. What is the efficiency of the engine?
A)0.57
B)1.35
C)2.35
D)0.7

Question

Quizplus · Accepted Answer

The efficiency of a Carnot engine is given by the formula: $\eta = 1 - \frac{Q_C}{Q_H}$, where $Q_H$ is the heat absorbed from the high-temperature reservoir and $Q_C$ is the heat rejected to the low-temperature reservoir. Substituting the given values, $\eta = 1 - \frac{225}{529} = 0.57$.

An Ideal Carnot Engine Extracts 529 J of Heat from a High-Temperature