A uniform, solid, cylindrical flywheel of radius 1.4 m and mass 15 kg rotates at $2.7 \mathrm { rad } / \mathrm { s }$ What is the magnitude of the flywheel's angular momentum?

Question

Quizplus · Accepted Answer

The angular momentum $ L $ of a solid cylinder is given by $ L = I \omega $, where $ I = \frac{1}{2} m r^2 $ is the moment of inertia. Substituting $ m = 15 \, \text{kg} $, $ r = 1.4 \, \text{m} $, and $ \omega = 2.7 \, \text{rad/s} $, we find $ L = \frac{1}{2} \times 15 \times (1.4)^2 \times 2.7 = 39.69 \approx 40 \, \text{kg} \cdot \text{m}^2/\text{s} $.

A Uniform, Solid, Cylindrical Flywheel of Radius 1 2.7rad/s2.7 \mathrm { rad } / \mathrm { s }2.7rad/s

A Uniform, Solid, Cylindrical Flywheel of Radius 1 $2.7 \mathrm { rad } / \mathrm { s }$