A vertical 30-cm steel rod, 1.0 cm in diameter, supports a 300-kg mass. What is the change in length of the rod caused by this mass? Young's modulus for steel is 2.0 × 10¹¹ N/m². A) 5.6 × 10^-⁵ m B) 6.5 × 10^-5 m C) 5.6 × 10^-6 m D) 6.5 × 10^-6 m E) 6.5 × 10^-4 m

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Quizplus · Accepted Answer

The change in length (ΔL) is calculated using the formula ΔL = (F * L) / (A * Y), where F is the force (mg), L is the original length, A is the cross-sectional area, and Y is Young's modulus. Substituting the given values, ΔL = (300 * 9.8 * 0.3) / (π * (0.005)^2 * 2.0 × 10^11) = 5.6 × 10^-5 m.

A Vertical 30-Cm Steel Rod, 1