A bacterium of genotype a⁺b⁺c⁺d⁺ is the donor in a cotransformation mapping. The recipient is a^-b^-c^-d^-. Data from the transformed cells (genotype and percent of each cotransformant) are shown below. What is the order of the genes? $$\begin{array} { l c } \text { Genotype } & \text { Cotransformants } \ a ^ { + } \text {and } b ^ { + } & 2 \% \ a ^ { + } \text {and } c ^ { + } & 0 \% \ a ^ { + } \text {and } d ^ { + } & 5 \% \ b ^ { + } \text {and } c ^ { + } & 5 \% \ b ^ { + } \text {and } a ^ { + } & 0 \% \ c ^ { + } \text {and } d ^ { + } & 0 \% \end{array}$$

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The Answer of A bacterium of genotype a⁺b⁺c⁺d⁺ is the donor in a cotransformation mapping. The recipient is a^-b^-c^-d^-. Data from the transformed cells (genotype and percent of each cotransformant) are shown below. What is the order of the genes? $$\begin{array} { l c } \text { Genotype } & \text { Cotransformants } \ a ^ { + } \text {and } b ^ { + } & 2 \% \ a ^ { + } \text {and } c ^ { + } & 0 \% \ a ^ { + } \text {and } d ^ { + } & 5 \% \ b ^ { + } \text {and } c ^ { + } & 5 \% \ b ^ { + } \text {and } a ^ { + } & 0 \% \ c ^ { + } \text {and } d ^ { + } & 0 \% \end{array}$$

A Bacterium of Genotype A+b+c+d+ Is the Donor in a Cotransformation

A Bacterium of Genotype A⁺b⁺c⁺d⁺ Is the Donor in a Cotransformation