If the recombination frequency between genes (A) and (B) is 5.3%, what is the distance between the genes in map units on the linkage map?
A) 53 m.u.
B) 5.3 m.u.
C) 0.53 m.u.
D) 10.6 m.u.
E) 25 m.u.

Question

Quizplus · Accepted Answer

The distance between genes in map units is equal to the recombination frequency between them. Therefore, the distance between genes (A) and (B) is 5.3 m.u.

If the Recombination Frequency Between Genes (A) and (B) Is