Human blood type is determined by three alleles I^A, I^B, and I^O. The alleles I^A and I^B are co-dominant to each other, and both are dominant to I^O. Within a large, randomly mating population (540,000 individuals), the frequencies for the blood type alleles are 0.3 for the I^A allele, 0.6 for the I^Oallele, and 0.1 for the I^B allele. Calculate the expected numbers of people in the population having each of the blood types A, B, AB, and O.

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The Hardy-Weinberg equation can be used to calculate the expected numbers of people in the population having each of the blood types. The equation is:p^2 + 2pq + q^2 = 1where p is the frequency of the dominant allele, q is the frequency of the recessive allele, and p^2, 2pq, and q^2 are the frequencies of the homozygous dominant, heterozygous, and homozygous recessive genotypes, respectively.In this case, the dominant alleles are I^A and I^B, and the recessive allele is I^O. The frequencies of the alleles are:p(I^A) = 0.3p(I^B) = 0.1q(I^O) = 0.6Using the Hardy-Weinberg equation, we can calculate the expected numbers of people in the population having each of the blood types:p(I^AI^A) = p^2 = 0.3^2 = 0.09p(I^AI^B) = 2pq = 2 * 0.3 * 0.1 = 0.06p(I^BI^B) = p^2 = 0.1^2 = 0.01p(I^AI^O) = 2pq = 2 * 0.3 * 0.6 = 0.36p(I^BI^O) = 2pq = 2 * 0.1 * 0.6 = 0.12p(I^OI^O) = q^2 = 0.6^2 = 0.36Multiplying these frequencies by the total population size (540,000), we get the expected numbers of people in the population having each of the blood types:A (I^AI^A or I^AI^O) = 0.09 * 540,000 + 0.36 * 540,000 = 243,000 peopleB (I^BI^B or I^BI^O) = 0.01 * 540,000 + 0.12 * 540,000 = 70,200 peopleAB (I^AI^B) = 0.06 * 540,000 = 32,400 peopleO (I^OI^O) = 0.36 * 540,000 = 194,400 peopleTherefore, the expected numbers of people in the population having each of the blood types are:A = 243,000 peopleB = 70,200 peopleAB = 32,400 peopleO = 194,400 people

Human Blood Type Is Determined by Three Alleles IA, IB

Human Blood Type Is Determined by Three Alleles I^A, I^B