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an Auxotrophic E

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An auxotrophic E. coli strain requires adenine to grow because of a mutation in a gene for an adenine synthesis enzyme. The following shows part of the wild-type and mutant alleles of the gene, including the start codon. The bottom strand is the template for transcription.  ade 1+wild-type allele  ade1 mutant allele  5’...TTATGGGCAAGATCCCA...3’  5’....TTA TGGGCTAGATCCCA...3’  3’...AATACCCGTTCTAGGGT...5’  3’...AATATGGGCTAGATCCCA...3’ \begin{array} { c c } \text { ade } 1 ^ { + } \text {wild-type allele } & \text { ade1 } ^ { - } \text {mutant allele } \\\text { 5'...TTATGGGCAAGATCCCA...3' } & \text { 5'....TTA TGGGCTAGATCCCA...3' } \\\text { 3'...AATACCCGTTCTAGGGT...5' } & \text { 3'...AATATGGGCTAGATCCCA...3' }\end{array}
-E. coli strains that have both the original ade1- mutant allele shown above and a mutant allele for a gene that encodes a lysine tRNA are able to make some normal ade1 enzyme. The mutant lysine tRNA allele makes a tRNA that has one base that is different from the wild-type tRNA. Which of the following statements would help explain how the lysine tRNA mutation allows synthesis of the normal ade1 enzyme? (Select all that apply.)


A) The mutation in the lysine tRNA gene changes the sequence of the anticodon.
B) The mutant tRNA pairs with UAG, a stop codon.
C) When the mRNA from the ade1- allele is being translated, a mutant tRNAlysine could incorporate a lysine into the protein, bypassing the mutant UAG.
D) The ade1- mutant would always result in a stop signal regardless of the mutant tRNA.
E) The mutant tRNA would always match with UAG and prevent normal termination of the polypeptide chain.

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