Use the following information to answer the question. A pescatarian is a person who eats fish and seafood but no other animal. An event planner does some research and finds that approximately 2.75% of the people in the area where a large event is to be held are pescatarian. Treat the 250 guests expected at the event as a simple random sample from the local population of about 150,000.
-On average, what proportion of the guests would be expected to be pescatarian, give or take how many? Round to the nearest whole person.
A)There is not enough information given to calculate expected value.
B)8 people, give or take 4 people
C)7 people, give or take 3 people
D)6 people, give or take 5 people

Question

Quizplus · Accepted Answer

The expected number of pescatarians is 2.75% of 250, which is approximately 7 people. The standard deviation for a binomial distribution is √(np(1-p)), which is about 3, so the expected number is 7 people, give or take 3 people.

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