A statement that displays the address of the variable num1 is
A) cout

Question

A statement that displays the address of the variable num1 is
A) cout << num1;.
B) cout << *num1;.
C) cout << &(*num1);.
D) cout << &num1;.
E) None of the above

Quizplus · Accepted Answer

The address of a variable can be obtained using '&' (ampersand) operator in C++. So, the correct statement that displays the address of the variable num1 is cout << &num1;. Option A prints the value of num1 and option B prints the value stored in the memory location pointed to by num1, which may not necessarily be the same as the address of num1 itself. Option C uses unnecessary dereferencing and the address-of operator cancels out the effect of the dereference. Therefore, option D is the correct choice.

A Statement That Displays the Address of the Variable Num1