In a population that is in Hardy-Weinberg equilibrium, the frequency of a particular dominant allele is 20 percent.What percentage of the individuals in this population will be heterozygous for that trait?
A)16 percent
B)32 percent
C)42 percent
D)64 percent
E)80 percent

Question

Quizplus · Accepted Answer

In Hardy-Weinberg equilibrium, the frequency of heterozygous individuals is calculated as 2pq, where p is the frequency of the dominant allele and q is the frequency of the recessive allele. If p = 0.2, then q = 0.8. Therefore, 2pq = 2(0.2)(0.8) = 0.32 or 32 percent.

In a Population That Is in Hardy-Weinberg Equilibrium, the Frequency