An erythrocyte is placed in a hypotonic solution of 100 mOsm. What will happen to the cell?
A) The cell swells to three times its original volume, Vf = 3Vo.
B) The cell shrinks to one half its original volume, Vf = 1/2 Vo.
C) The cell swells to twice its original volume, Vf = 2Vo.
D) The cell volume increases by one third, Vf = 4/3 Vo.
E) The cell volume remains unchanged.
Correct Answer:
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