What is the capacitance that stores 1.175 µC of charge and drops 25 V?
A)0.047 µF
B)47 µF
C)4.7 µF
D)0.47 µF

Name: What is the capacitance that stores 1.175 µC of charge and drops 25 V? A)0.047 µF B)47 µF C)4.7 µF D)0.47 µF
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Question

Quizplus · Accepted Answer

Capacitance (C) is calculated using the formula C = Q/V, where Q is the charge and V is the voltage. Substituting the given values, C = 1.175 µC / 25 V = 0.047 µF.

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