How much voltage is dropped across a 150 µF capacitor after 3.33 seconds if it is charged by a 50 V source through a 22 KΩ resistor?
A)49 V
B)43.3 V
C)31.8 V
D)47.5 V

Question

Quizplus · Accepted Answer

The voltage across a charging capacitor is given by V(t) = V0 * (1 - e^(-t/RC)). Here, V0 = 50 V, R = 22,000 Ω, C = 150 µF = 150 x 10^-6 F, and t = 3.33 s. Calculate the time constant τ = RC = 22,000 * 150 x 10^-6 = 3.3 s. Then, V(3.33) = 50 * (1 - e^(-3.33/3.3)) ≈ 31.8 V.

How Much Voltage Is Dropped Across a 150 µF Capacitor