The lower limit of the 90% confidence interval for $\mu$, where n = 64, = 70, and $\sigma$ = 20, is 65.89.

Question

The lower limit of the 90% confidence interval for $\mu$, where n = 64,  = 70, and $\sigma$ = 20, is 65.89.

Quizplus · Accepted Answer

Based on the given information, we can use the formula for a confidence interval for a normal population mean:
CI = X̄ ± zα/2(σ/√n)
Plugging in the values given, we get:
CI = F1F1F1S1μF1F1F10 ± 1.645(20/√64)
CI = F1F1F1S1μF1F1F10 ± 8.225
Since the lower limit of the interval is given as 65.89, we can set up an equation to solve for the sample mean:
65.89 = F1F1F1S1μF1F1F10 - 8.225
F1F1F1S1μF1F1F10 = 74.115
Therefore, the statement is true and the lower limit of the 90% confidence interval is indeed 65.89.

The Lower Limit of the 90% Confidence Interval For μ\muμ , Where N = 64, = 70, And

The Lower Limit of the 90% Confidence Interval For $\mu$ , Where N = 64, = 70, And