If two random samples of sizes n₁ and n₂ are selected independently from two populations with means $\mu$₁ and $\mu$₂, then the mean of equals: A) $\mu$₁ + $\mu$₂ B) $\mu$₁- $\mu$₂ C) $\mu$₁ / $\mu$₂ D) $\mu$₁ $\mu$₂

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Quizplus · Accepted Answer

The mean of the 11eae5f3_f283_a9ba_bcb4_1da0a6710c65_TB7453_11 is equal to the difference between the mean of the first population and the mean of the second population, multiplied by the ratio of their sample sizes, and added to the mean of the first sample. This can be expressed as: (mean of sample 1) + [(mean of population 1 - mean of population 2) x (sample size 1 / total sample size)] Substituting the given values, we get: F1F1F1S1F1F1F10₁ + [(F1F1F1S1F1F1F10₁ - F1F1F1S1F1F1F10₂) x (n₁ / (n₁ + n₂))] Simplifying: F1F1F1S1F1F1F10₁ + (F1F1F1S1F1F1F10₁ - F1F1F1S1F1F1F10₂) x (n₁ / (n₁ + n₂)) Simplifying further: F1F1F1S1F1F1F10₁ - (F1F1F1S1F1F1F10₁ - F1F1F1S1F1F1F10₂) x (n₂ / (n₁ + n₂)) This simplifies to: F1F1F1S1F1F1F10₁ - (F1F1F1S1F1F1F10₁ - F1F1F1S1F1F1F10₂) x (n₂ / (n₁ + n₂)) So, the mean of the 11eae5f3_f283_a9ba_bcb4_1da0a6710c65_TB7453_11 is given by option B.

If Two Random Samples of Sizes N1 and N2 Are μ\muμ

If Two Random Samples of Sizes N₁ and N₂ Are $\mu$