Assume the average height for American women is 64 inches with a standard deviation of 2 inches.What percent of groups of size 25 would have mean heights of more than 64.5 inches? (Round z score to two decimal places.)
A) 10.56
B) 22.82
C) 35.31
D) 89.44

Question

Quizplus · Accepted Answer

The standard error (SE) is the standard deviation divided by the square root of the sample size: SE = 2/√25 = 0.4. The z-score for 64.5 inches is (64.5 - 64) / 0.4 = 1.25. Using the z-table, the probability of a z-score greater than 1.25 is approximately 10.56%.

Assume the Average Height for American Women Is 64 Inches