For the data in the source table, what is the effect size for this one-way within-groups ANOVA? $$\begin{array} { | l | c | c c | c | }
\hline \text { Source } & \text { SS } & d f & M S & F \
\hline \text { Between-groups } & 12.159 & 3 & 4.053 & 2.98 \
\hline \text { Subjects } & 6.77 & 5 & 1.354 & 0.996 \
\hline \text { Within-groups } & 20.4 & 15 & 1.360 & \
\hline \text { Total } & 39.329 & 23 & & \
\hline
\end{array}$$
A) 0.249
B) 0.373
C) 0.664
D) 2.678

Question

For the data in the source table, what is the effect size for this one-way within-groups ANOVA? $$\begin{array} { | l | c | c c | c | } 
\hline \text { Source } & \text { SS } & d f & M S & F \
\hline \text { Between-groups } & 12.159 & 3 & 4.053 & 2.98 \
\hline \text { Subjects } & 6.77 & 5 & 1.354 & 0.996 \
\hline \text { Within-groups } & 20.4 & 15 & 1.360 & \
\hline \text { Total } & 39.329 & 23 & & \
\hline
\end{array}$$
A) 0.249
B) 0.373
C) 0.664
D) 2.678

Quizplus · Accepted Answer

The effect size for a one-way within-groups ANOVA can be calculated using the formula for partial eta squared ($\eta^2_p$), which is $\eta^2_p = \frac{SS_{between}}{SS_{between} + SS_{within}}$. Plugging in the values from the table, we get $\eta^2_p = \frac{12.159}{12.159 + 20.4} = \frac{12.159}{32.559} \approx 0.373$.

For the Data in the Source Table, What Is the Effect