Exhibit 6-10
A professor at a local university noted that the exam grades of her students were normally distributed with a mean of 73 and a standard deviation of 11.
-Refer to Exhibit 6-10. Students who made 57.93 or lower on the exam failed the course. What percent of students failed the course?
A)8.53%
B)18.53%
C)91.47%
D)0.853%

Question

Quizplus · Accepted Answer

To find the percentage of students who failed, calculate the z-score for 57.93 using the formula: z = (X - μ) / σ = (57.93 - 73) / 11 = -1.36. Using a standard normal distribution table, a z-score of -1.36 corresponds to approximately 8.53% of students.

Exhibit 6-10 A Professor at a Local University Noted That the Exam