Exhibit 8-5
A random sample of 64 SAT scores of students applying for merit scholarships showed an average of 1400 with a standard deviation of 240.
-Refer to Exhibit 8-5. If we want to provide a 95% confidence interval for the SAT scores, the degrees of freedom for reading the critical values of "t" statistic is
A)60
B)61
C)62
D)63

Question

Quizplus · Accepted Answer

The degrees of freedom for a t-distribution is calculated as the sample size minus one. Therefore, for a sample size of 64, the degrees of freedom is 64 - 1 = 63.

Exhibit 8-5 A Random Sample of 64 SAT Scores of Students Applying