Exhibit 10-13
Part of an ANOVA table is shown below.
$\begin{array}{lr}
\text { Source of } & \text { Sum of }& \text {Degrees}& \text {Mean}\
\text {Variation } &\text { Squares} & \text {of Freedom}& \text {Square}& \text {F}\
\text { Between Treatments} &64&&&8\
\text { Within Treatments } &&&2\
\text { Error} &\
\hline \text {Total } &100\
\end{array}$

-Refer to Exhibit 10-13. If at 95% confidence we want to determine whether or not the means of the populations are equal, the p-value is
A) greater than 0.1
B) between 0.05 to 0.1
C) between 0.025 to 0.05
D) less than 0.01

Question

Exhibit 10-13
Part of an ANOVA table is shown below.
 $\begin{array}{lr}
  \text { Source of } & \text { Sum of }& \text {Degrees}& \text {Mean}\
 \text {Variation  } &\text { Squares} & \text {of Freedom}& \text {Square}& \text {F}\
 \text {  Between Treatments} &64&&&8\
 \text { Within Treatments } &&&2\
 \text {  Error} &\
\hline \text {Total  } &100\
\end{array}$

-Refer to Exhibit 10-13. If at 95% confidence we want to determine whether or not the means of the populations are equal, the p-value is
A) greater than 0.1
B) between 0.05 to 0.1
C) between 0.025 to 0.05
D) less than 0.01

Quizplus · Accepted Answer

The F-value is calculated as the ratio of the mean square between treatments to the mean square within treatments, which is 8/2 = 4. With this F-value and the degrees of freedom, the p-value is less than 0.01, indicating strong evidence against the null hypothesis of equal means.

Exhibit 10-13 Part of an ANOVA Table Is Shown Below

Exhibit 10-13
Part of an ANOVA Table Is Shown Below