The number of people playing tennis T (in millions) in the United States from 2000 through 2007 can be approximated by the function
$T ( t ) = 0.0235 t ^ { 4 } - 0.3401 t ^ { 3 } + 2.556 t ^ { 2 } - 6.86 t + 23.8$
And the U.S.population P (in millions) from 2000 through 2007 can be approximated by the function $P ( t ) = 5.8 t + 224.5$ , where t represents the year, with t = 0 corresponding to 2000.
Evaluate the function $$h ( t ) = \frac { 0.0235 t ^ { 4 } - 0.3401 t ^ { 3 } + 2.556 t ^ { 2 } - 6.86 t + 23.8 } { 5.8 t + 224.5 }$$ for t = 0 and 3.
A)h(0) = 0.1060, h(3) = 0.0783
B)h(0) = 0.3060, h(3) = 0.2783
C)h(0) = -0.2060, h(3) = -0.1783
D)h(0) = 0.1783, h(3) = 0.2060
E)h(0) = -0.1060, h(3) = -0.0783

Question

The number of people playing tennis T (in millions) in the United States from 2000 through 2007 can be approximated by the function 
 $T ( t ) = 0.0235 t ^ { 4 } - 0.3401 t ^ { 3 } + 2.556 t ^ { 2 } - 6.86 t + 23.8$  
And the U.S.population P (in millions) from 2000 through 2007 can be approximated by the function $P ( t ) = 5.8 t + 224.5$ , where t represents the year, with t = 0 corresponding to 2000.
Evaluate the function $$h ( t ) = \frac { 0.0235 t ^ { 4 } - 0.3401 t ^ { 3 } + 2.556 t ^ { 2 } - 6.86 t + 23.8 } { 5.8 t + 224.5 }$$ for t = 0 and 3.
A)h(0) = 0.1060, h(3) = 0.0783
B)h(0) = 0.3060, h(3) = 0.2783
C)h(0) = -0.2060, h(3) = -0.1783
D)h(0) = 0.1783, h(3) = 0.2060
E)h(0) = -0.1060, h(3) = -0.0783

Quizplus · Accepted Answer

For t = 0, $h(0) = \frac{23.8}{224.5} = 0.1060$. For t = 3, substituting t = 3 into both the numerator and the denominator of $h(t)$ and simplifying gives $h(3) = 0.0783$.

The Number of People Playing Tennis T (In Millions) in the United