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Select a Right Triangle Corresponding to the Trigonometric Function of the Acute

Question 256

Multiple Choice

Select a right triangle corresponding to the trigonometric function of the acute angle $\theta$ .Use the Pythagorean Theorem to determine the third side and then find the other five trigonometric functions of $\theta$ .
Tan $\theta$ = $\frac { 5 } { 12 }$

Sin $\theta$ = $\frac { 5 } { 13 }$ csc $\theta$ = $\frac { 13 } { 5 }$ cos $\theta$ = $\frac { 12 } { 13 }$ sec $\theta$ = $\frac { 13 } { 12 }$ tan $\theta$ = $\frac { 5 } { 12 }$ cot $\theta$ = $\frac { 12 } { 5 }$

A) $Select a right triangle corresponding to the trigonometric function of the acute angle \theta .Use the Pythagorean Theorem to determine the third side and then find the other five trigonometric functions of \theta . Tan \theta = \frac { 5 } { 12 } Sin \theta = \frac { 5 } { 13 } csc \theta = \frac { 13 } { 5 } cos \theta = \frac { 12 } { 13 } sec \theta = \frac { 13 } { 12 } tan \theta = \frac { 5 } { 12 } cot \theta = \frac { 12 } { 5 } A) sin \theta = \frac { 5 } { 13 } csc \theta = \frac { 13 } { 5 } cos \theta = \frac { 12 } { 13 } sec \theta = \frac { 13 } { 12 } tan \theta = \frac { 5 } { 12 } cot \theta = \frac { 12 } { 5 } B) sin \theta = \frac { 5 } { 13 } csc \theta = \frac { 5 } { 12 } cos \theta = \frac { 12 } { 13 } sec \theta = \frac { 12 } { 5 } tan \theta = \frac { 13 } { 5 } cot \theta = \frac { 13 } { 12 } C) sin \theta = \frac { 13 } { 12 } csc \theta = \frac { 13 } { 5 } cos \theta = \frac { 12 } { 5 } sec \theta = \frac { 5 } { 13 } tan \theta = \frac { 5 } { 12 } cot \theta = \frac { 12 } { 13 } D) sin \theta = \frac { 13 } { 5 } csc \theta = \frac { 5 } { 13 } cos \theta = \frac { 13 } { 12 } sec \theta = \frac { 12 } { 13 } tan \theta = \frac { 12 } { 5 } cot \theta = \frac { 5 } { 12 } E) sin \theta = \frac { 12 } { 5 } csc \theta = \frac { 5 } { 12 } cos \theta = \frac { 13 } { 12 } sec \theta = \frac { 12 } { 13 } tan \theta = \frac { 13 } { 5 } cot \theta = \frac { 5 } { 13 }$ sin $\theta$ = $\frac { 5 } { 13 }$ csc $\theta$ = $\frac { 13 } { 5 }$ cos $\theta$ = $\frac { 12 } { 13 }$ sec $\theta$ = $\frac { 13 } { 12 }$ tan $\theta$ = $\frac { 5 } { 12 }$ cot $\theta$ = $\frac { 12 } { 5 }$
B) $Select a right triangle corresponding to the trigonometric function of the acute angle \theta .Use the Pythagorean Theorem to determine the third side and then find the other five trigonometric functions of \theta . Tan \theta = \frac { 5 } { 12 } Sin \theta = \frac { 5 } { 13 } csc \theta = \frac { 13 } { 5 } cos \theta = \frac { 12 } { 13 } sec \theta = \frac { 13 } { 12 } tan \theta = \frac { 5 } { 12 } cot \theta = \frac { 12 } { 5 } A) sin \theta = \frac { 5 } { 13 } csc \theta = \frac { 13 } { 5 } cos \theta = \frac { 12 } { 13 } sec \theta = \frac { 13 } { 12 } tan \theta = \frac { 5 } { 12 } cot \theta = \frac { 12 } { 5 } B) sin \theta = \frac { 5 } { 13 } csc \theta = \frac { 5 } { 12 } cos \theta = \frac { 12 } { 13 } sec \theta = \frac { 12 } { 5 } tan \theta = \frac { 13 } { 5 } cot \theta = \frac { 13 } { 12 } C) sin \theta = \frac { 13 } { 12 } csc \theta = \frac { 13 } { 5 } cos \theta = \frac { 12 } { 5 } sec \theta = \frac { 5 } { 13 } tan \theta = \frac { 5 } { 12 } cot \theta = \frac { 12 } { 13 } D) sin \theta = \frac { 13 } { 5 } csc \theta = \frac { 5 } { 13 } cos \theta = \frac { 13 } { 12 } sec \theta = \frac { 12 } { 13 } tan \theta = \frac { 12 } { 5 } cot \theta = \frac { 5 } { 12 } E) sin \theta = \frac { 12 } { 5 } csc \theta = \frac { 5 } { 12 } cos \theta = \frac { 13 } { 12 } sec \theta = \frac { 12 } { 13 } tan \theta = \frac { 13 } { 5 } cot \theta = \frac { 5 } { 13 }$ sin $\theta$ = $\frac { 5 } { 13 }$ csc $\theta$ = $\frac { 5 } { 12 }$ cos $\theta$ = $\frac { 12 } { 13 }$ sec $\theta$ = $\frac { 12 } { 5 }$ tan $\theta$ = $\frac { 13 } { 5 }$ cot $\theta$ = $\frac { 13 } { 12 }$
C) $Select a right triangle corresponding to the trigonometric function of the acute angle \theta .Use the Pythagorean Theorem to determine the third side and then find the other five trigonometric functions of \theta . Tan \theta = \frac { 5 } { 12 } Sin \theta = \frac { 5 } { 13 } csc \theta = \frac { 13 } { 5 } cos \theta = \frac { 12 } { 13 } sec \theta = \frac { 13 } { 12 } tan \theta = \frac { 5 } { 12 } cot \theta = \frac { 12 } { 5 } A) sin \theta = \frac { 5 } { 13 } csc \theta = \frac { 13 } { 5 } cos \theta = \frac { 12 } { 13 } sec \theta = \frac { 13 } { 12 } tan \theta = \frac { 5 } { 12 } cot \theta = \frac { 12 } { 5 } B) sin \theta = \frac { 5 } { 13 } csc \theta = \frac { 5 } { 12 } cos \theta = \frac { 12 } { 13 } sec \theta = \frac { 12 } { 5 } tan \theta = \frac { 13 } { 5 } cot \theta = \frac { 13 } { 12 } C) sin \theta = \frac { 13 } { 12 } csc \theta = \frac { 13 } { 5 } cos \theta = \frac { 12 } { 5 } sec \theta = \frac { 5 } { 13 } tan \theta = \frac { 5 } { 12 } cot \theta = \frac { 12 } { 13 } D) sin \theta = \frac { 13 } { 5 } csc \theta = \frac { 5 } { 13 } cos \theta = \frac { 13 } { 12 } sec \theta = \frac { 12 } { 13 } tan \theta = \frac { 12 } { 5 } cot \theta = \frac { 5 } { 12 } E) sin \theta = \frac { 12 } { 5 } csc \theta = \frac { 5 } { 12 } cos \theta = \frac { 13 } { 12 } sec \theta = \frac { 12 } { 13 } tan \theta = \frac { 13 } { 5 } cot \theta = \frac { 5 } { 13 }$ sin $\theta$ = $\frac { 13 } { 12 }$ csc $\theta$ = $\frac { 13 } { 5 }$ cos $\theta$ = $\frac { 12 } { 5 }$ sec $\theta$ = $\frac { 5 } { 13 }$ tan $\theta$ = $\frac { 5 } { 12 }$ cot $\theta$ = $\frac { 12 } { 13 }$
D) $Select a right triangle corresponding to the trigonometric function of the acute angle \theta .Use the Pythagorean Theorem to determine the third side and then find the other five trigonometric functions of \theta . Tan \theta = \frac { 5 } { 12 } Sin \theta = \frac { 5 } { 13 } csc \theta = \frac { 13 } { 5 } cos \theta = \frac { 12 } { 13 } sec \theta = \frac { 13 } { 12 } tan \theta = \frac { 5 } { 12 } cot \theta = \frac { 12 } { 5 } A) sin \theta = \frac { 5 } { 13 } csc \theta = \frac { 13 } { 5 } cos \theta = \frac { 12 } { 13 } sec \theta = \frac { 13 } { 12 } tan \theta = \frac { 5 } { 12 } cot \theta = \frac { 12 } { 5 } B) sin \theta = \frac { 5 } { 13 } csc \theta = \frac { 5 } { 12 } cos \theta = \frac { 12 } { 13 } sec \theta = \frac { 12 } { 5 } tan \theta = \frac { 13 } { 5 } cot \theta = \frac { 13 } { 12 } C) sin \theta = \frac { 13 } { 12 } csc \theta = \frac { 13 } { 5 } cos \theta = \frac { 12 } { 5 } sec \theta = \frac { 5 } { 13 } tan \theta = \frac { 5 } { 12 } cot \theta = \frac { 12 } { 13 } D) sin \theta = \frac { 13 } { 5 } csc \theta = \frac { 5 } { 13 } cos \theta = \frac { 13 } { 12 } sec \theta = \frac { 12 } { 13 } tan \theta = \frac { 12 } { 5 } cot \theta = \frac { 5 } { 12 } E) sin \theta = \frac { 12 } { 5 } csc \theta = \frac { 5 } { 12 } cos \theta = \frac { 13 } { 12 } sec \theta = \frac { 12 } { 13 } tan \theta = \frac { 13 } { 5 } cot \theta = \frac { 5 } { 13 }$ sin $\theta$ = $\frac { 13 } { 5 }$ csc $\theta$ = $\frac { 5 } { 13 }$ cos $\theta$ = $\frac { 13 } { 12 }$ sec $\theta$ = $\frac { 12 } { 13 }$ tan $\theta$ = $\frac { 12 } { 5 }$ cot $\theta$ = $\frac { 5 } { 12 }$
E) $Select a right triangle corresponding to the trigonometric function of the acute angle \theta .Use the Pythagorean Theorem to determine the third side and then find the other five trigonometric functions of \theta . Tan \theta = \frac { 5 } { 12 } Sin \theta = \frac { 5 } { 13 } csc \theta = \frac { 13 } { 5 } cos \theta = \frac { 12 } { 13 } sec \theta = \frac { 13 } { 12 } tan \theta = \frac { 5 } { 12 } cot \theta = \frac { 12 } { 5 } A) sin \theta = \frac { 5 } { 13 } csc \theta = \frac { 13 } { 5 } cos \theta = \frac { 12 } { 13 } sec \theta = \frac { 13 } { 12 } tan \theta = \frac { 5 } { 12 } cot \theta = \frac { 12 } { 5 } B) sin \theta = \frac { 5 } { 13 } csc \theta = \frac { 5 } { 12 } cos \theta = \frac { 12 } { 13 } sec \theta = \frac { 12 } { 5 } tan \theta = \frac { 13 } { 5 } cot \theta = \frac { 13 } { 12 } C) sin \theta = \frac { 13 } { 12 } csc \theta = \frac { 13 } { 5 } cos \theta = \frac { 12 } { 5 } sec \theta = \frac { 5 } { 13 } tan \theta = \frac { 5 } { 12 } cot \theta = \frac { 12 } { 13 } D) sin \theta = \frac { 13 } { 5 } csc \theta = \frac { 5 } { 13 } cos \theta = \frac { 13 } { 12 } sec \theta = \frac { 12 } { 13 } tan \theta = \frac { 12 } { 5 } cot \theta = \frac { 5 } { 12 } E) sin \theta = \frac { 12 } { 5 } csc \theta = \frac { 5 } { 12 } cos \theta = \frac { 13 } { 12 } sec \theta = \frac { 12 } { 13 } tan \theta = \frac { 13 } { 5 } cot \theta = \frac { 5 } { 13 }$ sin $\theta$ = $\frac { 12 } { 5 }$ csc $\theta$ = $\frac { 5 } { 12 }$ cos $\theta$ = $\frac { 13 } { 12 }$ sec $\theta$ = $\frac { 12 } { 13 }$ tan $\theta$ = $\frac { 13 } { 5 }$ cot $\theta$ = $\frac { 5 } { 13 }$

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