You are skiing down a mountain with a vertical height of 1250 feet.The distance from the top of the mountain to the base is 2500 feet.What is the angle of elevation from the base to the top of the mountain
A)60° = $\frac { \pi } { 3 }$
B)30° = $\frac { \pi } { 6 }$
C)0° = 0
D)90° = $\frac { \pi } { 2 }$
E)45° = $\frac { \pi } { 4 }$

Question

You are skiing down a mountain with a vertical height of 1250 feet.The distance from the top of the mountain to the base is 2500 feet.What is the angle of elevation from the base to the top of the mountain  
A)60° = $\frac { \pi } { 3 }$
B)30° = $\frac { \pi } { 6 }$
C)0° = 0
D)90° = $\frac { \pi } { 2 }$
E)45° = $\frac { \pi } { 4 }$

Quizplus · Accepted Answer

The angle of elevation can be found using the tangent function in trigonometry, where tan(θ) = opposite/adjacent. Here, the opposite side is the vertical height (1250 feet) and the adjacent side is the distance from the top to the base (2500 feet). Thus, tan(θ) = 1250/2500 = 1/2. The angle whose tangent is 1/2 is 30° or $\frac{\pi}{6}$.

You Are Skiing Down a Mountain with a Vertical Height π3\frac { \pi } { 3 }3π​

You Are Skiing Down a Mountain with a Vertical Height $\frac { \pi } { 3 }$