Find the point $( x , y )$ on the unit circle that corresponds to the real number $t = \frac { 5 \pi } { 4 }$ .Use your results to evaluate $\tan$ .
A) $\tan t = \frac { \sqrt { 2 } } { 2 }$
B) $\tan t = 0$
C) $\tan t = - \frac { \sqrt { 2 } } { 2 }$
D) $\tan t = 1$
E) $\tan t = \text { undefined }$

Question

Quizplus · Accepted Answer

The point on the unit circle for $t = \frac{5\pi}{4}$ is $(- \frac{\sqrt{2}}{2}, - \frac{\sqrt{2}}{2})$. The tangent is $\tan t = \frac{y}{x} = \frac{-\frac{\sqrt{2}}{2}}{-\frac{\sqrt{2}}{2}} = 1$.

Find the Point (x,y)( x , y )(x,y) On the Unit Circle That Corresponds to the Real Number

Find the Point $( x , y )$ On the Unit Circle That Corresponds to the Real Number