Seven hundred gallons of 89-octane gasoline is obtained by mixing 87-octane gasoline with 92-octane gasoline.How much of each type of gasoline is required to obtain the 700 gallons of 89-octane gasoline? Use this system of linear equations there x and y represent the number of gallons of the 87-octane gasoline and 89-octane gasoline. $\left\{ \begin{array} { c }
x + y = 700 \
87 x + 92 y = 62300
\end{array} \right.$

Question

Seven hundred gallons of 89-octane gasoline is obtained by mixing 87-octane gasoline with 92-octane gasoline.How much of each type of gasoline is required to obtain the 700 gallons of 89-octane gasoline? Use this system of linear equations there x and y represent the number of gallons of the 87-octane gasoline and 89-octane gasoline.   $\left\{ \begin{array} { c } 
x + y = 700 \
87 x + 92 y = 62300
\end{array} \right.$

Quizplus · Accepted Answer

The system of equations represents a mixture problem where the total volume and the weighted average for octane levels are given. Solving the system yields 420 gallons of 87-octane and 280 gallons of 92-octane gasoline.

Seven Hundred Gallons of 89-Octane Gasoline Is Obtained by Mixing {x+y=70087x+92y=62300\left\{ \begin{array} { c } x + y = 700 \\87 x + 92 y = 62300\end{array} \right.{x+y=70087x+92y=62300​

Seven Hundred Gallons of 89-Octane Gasoline Is Obtained by Mixing $\left\{ \begin{array} { c } x + y = 700 \\87 x + 92 y = 62300\end{array} \right.$